Category:power
Question:
there is a conveyor belt with the four transmission system, respectively, with four electric motors M1 ~ M4-driven, the control requirements are as follows:
⑴ start, first start the last one belts, each 2s delay after the start followed by the other belt machine, the M4 M3 M2 M1.
⑵ stop, first stop the top of a leather belt, each 5s delay after the cessation of the other belt machine in turn, namely, M1 M2 M3 M4.
⑶ failure when a belt conveyor, the conveyor belt and in front of an immediate stop, while the back belt according to the order to stop parking.
my design, such as accessories, but it seems that does not meet the third condition. Hope that we can help me look. Grateful! ! !
Answer:
even done a bit for reference, G1 ~ G4, respectively M1 ~ M4 of the fault signal, T1 ~ T6 to time relay (power type), M10 ~ M13 intermediate relay, M1 ~ M4 for the output relay, even the absence of a specific address
Chinese:问一道PLC题
类别: 电力
问题:
有一个用四条皮带运输机的传输系统，分别用四台电动机M1~M4驱动，控制要求如下：
⑴启动时，先启动{zh1}一条皮带，每延时2s后，依次启动其他皮带机，即M4 M3 M2 M1 。
⑵停止时，先停止最前面一条皮带，每延时5s后，依次停止其他皮带机，即M1 M2 M3 M4 。
⑶当某皮带机发生故障时，该皮带机及其前面的皮带机立即停下，而后面的皮带机按停止顺序依次停车。
我的设计如附件,但好像不能满足第三个条件。希望大家能够帮我解答一下。不胜感激！！！
回答:
偶做了一下供参考，G1～G4分别为M1～M4的故障信号，T1～T6为时间继电器（通电型），M10～M13为中间继电器，M1～M4为输出继电器，具体地址偶没设
