旋转矩阵算法

问题：

     打印形如

             1   8   7

             2   9   6

             3   4   5

     的N阶矩阵

CODE：

#include <stdio.h>
#include <stdlib.h>
int main()
{
    int m = 0;
    int now_n = 1;
    int left,right;
    int up,down;
    int i = 1,j = 1;
    int a[10][10];
    printf("input your m:");
    scanf("%d",&m);
    printf("m is %d\n",m);
    left = 1;
    right = m;
    up = 1;
    down = m;
    while(left <=right && up <= down)
    {
        for(i = left ; i <= right ; i++)
            a[i][j] = now_n++;
        up += 1;
        i -= 1;
        printf("now_n is %d\n",now_n);
        for(j = up ; j <= down ; j++)
            a[i][j] = now_n++;
        right -= 1;
        j -= 1;
        for(i = right ; i >= left ; i--)
            a[i][j] = now_n++;
        down -= 1;
        i += 1;
        for(j = down ; j >= up ; j--)
            a[i][j] = now_n++;
        left += 1;
        j += 1;
    }
    for(i = 1 ; i <= m ; i++)
    {
        for(j = 1 ; j <= m ; j++)
        {
            printf("%3d",a[i][j]);
        }
        printf("\n");
    }
    system("pause");
    return 0;  
}