8X8点阵原理及驱动_黑暗幽灵_新浪博客

8X8点阵的实际外观图如下:

一共64个发光点构成,上下两排引脚,每排8个,一共16个

点阵侧面有文字的那面对准自己,

                (图 1)

 

8X8点阵的显示原理:

8X8点阵共由64个发光二极管组成,且每个发光二极管是



                               (图 2)



8*8点阵实际的引脚(图一)的不是一排阳极,一排阴极,(就像键盘一样不是abcd按顺序排的)所以焊接有点麻烦,8×8LED点阵引脚图如下:

1,2,3,4,5,6,7,8是行(阳极)

a,b,c,d,e,f,g,h是列(阴极)//此处说的都是行阳型8*8点阵,行阴的略

外面的1~16就是实际的管脚,见图一



 


74HC595是一个串入并出的芯片,通过一个for(i=0;i<8;i++)来存储数据。
具体来说就是{dy}个时钟信号来到时低位的数据向高位挪动一位,
在这个程序中是SH_CP 信号,当SH_CP是一个上跳沿时,
传入的形参Data与0x80相与,得到的数为1,则通过SDATA置1,否通过置为0,
并存储在74HC595的相应位置({zd1}位即Q0那)上,
DS内部也自动左移一位数据
然后dat向左移一位,使次高位变为{zg}位与0x80相与,
并存储。通过8次后,就可以得到数据,并存储在Q0~Q7中了,
这时ST_CP一个上跳沿,数据即送出去了.

显示0~59

C语言代码:

#include<AT89X52.h>

#define uchar unsigned char
#define uint unsigned int


void Ser_IN(uchar Data)
{
   uchar i;
   for(i=0;i<8;i++)
   {
     SH_CP=0;     //先置为低
  DS=Data&0x80;//取数据的{zg}位
  Data<<=1;   //讲数据的次高位移到{zg}位,为下一次取数据做准备
  SH_CP=1;   // 再置为高,产生移位时钟上升沿,储存器里的数据移位,数据输入
   }
}


void Par_OUT(void)
{
  ST_CP=0; //先置为低
  ST_CP=1; //再置为高,产生时钟上升沿,上升沿时,数据并行输出
}

uchar code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; //列
uchar code tabdigit[60][8]={    //字模取模方向 阴码 逆向逐列式
{0x00,0x3E,0x41,0x41,0x3E,0x00,0x00,0x00},
{0x00,0x42,0x7F,0x40,0x00,0x00,0x00,0x00},
{0x00,0x62,0x51,0x49,0x46,0x00,0x00,0x00},
{0x00,0x22,0x49,0x49,0x36,0x00,0x00,0x00},
{0x00,0x38,0x26,0x7F,0x20,0x00,0x00,0x00},
{0x00,0x4F,0x49,0x49,0x31,0x00,0x00,0x00},
{0x00,0x3E,0x49,0x49,0x32,0x00,0x00,0x00},
{0x00,0x03,0x71,0x09,0x07,0x00,0x00,0x00},
{0x00,0x36,0x49,0x49,0x36,0x00,0x00,0x00},
{0x00,0x26,0x49,0x49,0x3E,0x00,0x00,0x00},
{0x02,0xFF,0x00,0x00,0xFF,0x81,0xFF,0x00},
{0x02,0xFF,0x00,0x02,0xFF,0x00,0x00,0x00},
{0x02,0xFF,0x00,0xF3,0x91,0x99,0xCF,0x00},
{0x02,0xFF,0x00,0x42,0x89,0x89,0x89,0x76},
{0x02,0xFF,0x00,0x1C,0x13,0x10,0xFF,0x10},
{0x02,0xFF,0x00,0x4F,0x89,0x89,0x89,0x71},
{0x02,0xFF,0x00,0x7C,0x92,0x91,0x91,0x60},
{0x02,0xFF,0x00,0x01,0xF9,0x05,0x03,0x00},
{0x02,0xFF,0x00,0x76,0x89,0x89,0x89,0x76},
{0x02,0xFF,0x00,0x4E,0x91,0x91,0x91,0x7E},
{0xE2,0x91,0x89,0x86,0x00,0xFF,0x81,0xFF},
{0xE2,0x91,0x89,0x86,0x00,0x02,0xFF,0x00},
{0x79,0x49,0x4F,0x00,0x7A,0x4A,0x4E,0x00},
{0x79,0x49,0x4F,0x00,0x49,0x49,0x49,0x36},
{0x79,0x49,0x4F,0x00,0x1E,0x10,0xFF,0x10},
{0x79,0x49,0x4F,0x00,0x4E,0x4A,0x7A,0x00},
{0x79,0x49,0x4F,0x00,0xFE,0x92,0x92,0x60},
{0x79,0x49,0x4F,0x00,0x79,0x05,0x03,0x00},
{0x79,0x49,0x4F,0x00,0x76,0x89,0x89,0x76},
{0x79,0x49,0x4F,0x00,0x4E,0x91,0x91,0x7E},
{0x42,0x89,0x89,0x76,0x00,0xFE,0x82,0xFE},
{0x42,0x89,0x89,0x76,0x00,0x02,0xFF,0x00},
{0x42,0x89,0x89,0x76,0x00,0xF9,0x89,0x8F},
{0x42,0x89,0x89,0x76,0x00,0x89,0x89,0xFF},
{0x42,0x89,0x89,0x76,0x00,0x0F,0x08,0xFF},
{0x42,0x89,0x89,0x76,0x00,0x9E,0x92,0xF2},
{0x42,0x89,0x89,0x76,0x00,0xFF,0x89,0xF9},
{0x42,0x89,0x89,0x76,0x01,0x01,0xFD,0x03},
{0x42,0x89,0x89,0x76,0x00,0xFF,0x89,0xFF},
{0x42,0x89,0x89,0x76,0x00,0xCF,0x89,0xFF},
{0x1F,0x10,0xFF,0x00,0x7E,0x81,0x81,0x7E},
{0x1F,0x10,0xFF,0x00,0x02,0xFF,0x00,0x00},
{0x1F,0x10,0xFF,0x00,0xE2,0x91,0x89,0xC6},
{0x1F,0x10,0xFF,0x00,0x42,0x89,0x89,0x76},
{0x1F,0x10,0xFF,0x00,0x1E,0x10,0xFF,0x10},
{0x1F,0x10,0xFF,0x00,0x8F,0x89,0x89,0xF9},
{0x1F,0x10,0xFF,0x00,0xFF,0x89,0x89,0xF9},
{0x1F,0x10,0xFF,0x00,0x03,0xF9,0x05,0x03},
{0x0F,0x08,0xFF,0x00,0x76,0x89,0x89,0x76},
{0x1F,0x10,0xFF,0x00,0x4E,0x91,0x91,0x7E},
{0x4F,0x49,0x79,0x00,0x3E,0x41,0x41,0x3E},
{0x4F,0x49,0x79,0x00,0x00,0x02,0x7F,0x00},
{0x4F,0x49,0x79,0x00,0x62,0x51,0x49,0x46},
{0x4F,0x49,0x79,0x00,0x42,0x89,0x89,0x76},
{0x4F,0x49,0x79,0x00,0x1E,0x10,0x7E,0x10},
{0x4F,0x49,0x79,0x00,0x4F,0x49,0x79,0x00},
{0x4F,0x49,0x79,0x00,0x7F,0x49,0x79,0x00},
{0x4F,0x49,0x79,0x00,0x01,0x7D,0x03,0x01},
{0x4F,0x49,0x79,0x00,0x76,0x89,0x89,0x76},
{0x4F,0x49,0x79,0x00,0x0E,0x91,0x91,0x7E},
};
void t0(void) interrupt 1
{
  TH0=(65536-1000)/256;
  TL0=(65536-1000)%256;
  Ser_IN(tab[a]);   //8X8点阵列扫描
  Ser_IN(tabdigit[b][a]);//送行扫描数据
  Par_OUT();     //显示
  a++;
  if(a==8)
  {
   a=0;
  }
  timecount++;
  if(timecount==1000)
  {
   timecount=0;
 b++;
 if(b==60)
 {
   b=0;
 }
  }
}






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