怎样计算齿轮泵在工作中的流量

原文:
 在齿轮泵中,一对啮合着的、齿数相同的齿轮安装于壳体内部,齿轮的两端面由端盖密封,这样两个齿轮就在壳体内腔分成了左、右两个密封的油腔,并且每个齿间都形成一个密封的工作容积。当齿轮按图示方向旋转时,轮齿从右侧退出啮合,露出齿间,使该腔容积增大,形成局都真空,油箱中的油液在大气压力的作用下,经液压泵的吸油管进入右腔(吸油腔),完成吸油过程。随着齿轮的转动,每个轮齿的齿间把油液从右腔带入左腔。轮齿在左腔进人啮合,齿间被对方的轮齿占了位置,于是容积减小,齿间里的油液逐渐被挤出,使左腔的油压升高,油液从排油口输出,完成压油过程,而左腔即是泵的排油腔。两齿轮不断地转动,泵的吸油口和排油口便连续不断地吸油与排油,使泵不停地向系统供油 。 从能量转换的角度来看,齿轮泵是完成系统的{dy}次能量转换的装置,即把电动机输出的机械能转换成油液的液压能。 (一)齿轮泵的流量 1.理论上带到排出腔的油液体积应等于齿间工作容积。 2.每转的Qt应为两个齿轮全部齿间工作容积之和。 3.可假设齿间工作容积与齿的有效体积相等。 4.每转Qt 1)是一个齿轮的齿间工作容积与轮齿有效体积的总和 2)近似等于齿的有效部分所扫过的一个径向宽度为2m(m为模数)的环形体积 (二) 用上述计算泵的Qt时,数值偏小 应乘上修正系数K。平均Qt为: Qt=K· D·2m·B·n×10-6 L/min 式中:D——分度圆直径,mm; m——模数,mm; B——齿宽,mm; n——转速,r/min; K——修正系数,一般为1.05~1.15。 中、低压齿轮泵为使流量公式 Qt=6.66zm2Bn•10-6 n L/min (2—4) 高压齿轮泵的流量公式: Qt=7zm2Bn•10-6 L/min (2—5) (三)提高齿轮泵理论流量的途径 增加齿轮的直径、齿宽、转速n和减少齿数。 n过高会使轮齿转过吸入腔的时间过短 n和直径增加使齿轮的圆周速度增加,离心力加大 1.增加吸入困难,齿根处油压p降低,可能析出气体,导致Q减小,造成振动和产生噪声,甚至使泵无法工作 2.故{zd0}圆周速度应根据所输油的粘度而予以限制, 1){zd0}圆周速度不超过5~6m/s, 2){zg}转速一般在3000r/min左右。 加大齿宽会使径向力增大,齿面接触线加长,不易保持良好的密封。 减少齿数虽可使齿间容积V加大而Q增加,但会使Q的不均匀度加重。


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译文:
In the gear pump, a pair of engagement with, and the same number of teeth of gears mounted on the shell interior, the gear surface at both ends sealed by the cover, so the two gears in the shell cavity divided into right and left two sealed oil chamber , and each interdental are working to form a sealed volume. When the gear as shown in the direction of rotation, the teeth out of engagement from the right side, exposing between teeth, so that the cavity volume increases, the formation of Council are vacuum, the oil tank under the atmospheric pressure by the suction pump tube into the right chamber (suction chamber), oil absorption process to complete. As the gears rotate, each tooth cavity between teeth to the oil right into the left chamber. Into the tooth cavity in the left gear, the other side of the tooth between teeth are accounted for here, then volume decreases, between teeth where the oil is gradually being squeezed out, so that the left chamber of the oil pressure increases, the oil from the oil discharge I output to complete the process of pressing the oil, while the left chamber is pumping oil discharge chamber. Two gears constantly turning, the pump suction port and exhaust port will continuously absorbing the oil and discharges of oil, keep the pump oil to the system. From the perspective of energy conversion, gear pump is the first complete system of energy conversion device, that is, the motor output of mechanical energy into hydraulic oil can. (A) the flow gear pump 1. Theoretically, the volume of oil into the discharge chamber volume should be equal to the work between teeth. 2. Every turn of Qt should be two gears working volume of between teeth and all. 3. May assume that volume of work between teeth and teeth of the effective volume equal. 4. Every turn Qt 1) is a gear tooth between teeth working volume and the sum of the effective volume 2) is approximately equal to the effective part of the tooth by the sweep of a radial width of 2m (m as the modulus) of the ring size (B) Qt pump with the above calculation, the value is smaller Should be multiplied by the correction factor K. Average Qt as follows: Qt = K · D · 2m · B · n × 10-6 L / min The formula: D - pitch circle diameter, mm; m - modulus, mm; B - Tooth width, mm; n - rotational speed, r / min; K - correction factor, usually 1.05 to 1.15. , The low pressure gear pump to flow formula Qt = 6.66zm2Bn • 10-6 n L / min (2-4) High-pressure gear pump flow formula: Qt = 7zm2Bn • 10-6 L / min (2-5) (C) improve the ways Gear Pump Flow Increase the diameter of gear, tooth width, speed n and reduce the number of teeth. n is too high, turn the tooth of time is too short inhalation chamber n and the diameter of the circle to increase the speed of gear increases, the centrifugal force to increase 1. Increase the difficulty inhaling the tooth root of the lower oil pressure p may be precipitated gas, resulting in Q decreases, causing vibration and noise generated, and even the pump does not work 2. Therefore, the maximum circumferential speed should be restricted at the viscosity of oil, 1) Maximum circumferential speed of not more than 5 ~ 6m / s, 2) The maximum speed is generally around 3000r/min. Tooth width will increase the radial force increases tooth contact line extended and difficult to maintain a good seal. Although the number of teeth between teeth can reduce the volume increase and Q V increased, while the uneven degree of Q will increase.


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